Random php script

kaz · 07-23-2004, 03:30 AM

I got the idea from www.cosforums when the banner changes every new page

Code:

<?
# Put the SERVER PATH to image directory.
# INCLUDE trailing slash
$dir = "/home/deathqe/public_html/forum/randphotos/";
# Put the HTML PATH to image directory.
# DO NOT include trailing slash 
$html_dir = "http://www.death-eater.net/forum/randphotos";
$dir_handle = opendir($dir);
$image_array = array();
# This opens up the image directory, grabs all files with a ".jpg" extension
# and puts them into an array. You can set whatever extension you'd like here.
# Just switch out the .jpg for .gif, etc. If you have more than one extension,
# replace this line with something like this:
# if (($file !=".") && ($file !="..") && (substr($file, -4) == ".jpg") || (substr($file, -4) == ".gif"))) {
# This will pull up all .jpg OR .gifs. If you name all the images you want to pull
# a certain way (example, image-thumb.jpg or image.thumb.jpg) you can do this:
# if (($file !=".") && ($file !="..") && (substr($file, -10) == ".thumb.jpg")) {
# basically you want to put the extension in quotes and then count how many characters
# it is and place that after $file, -
while ($file = readdir($dir_handle)) {
if (($file !=".") && ($file !="..") && (substr($file, -4) == ".jpg")) {
$file_name = "$html_dir/$file";
$image_array[$file_name] = $file_name;
}
}
# sorts the array. For some reason this won't work at all
# unless this is done. Can anyone tell me why?
sort($image_array);
$count = sizeof($image_array);
# trims all the URLs of whitespace and assigns each
# item in the array a number to identify it.
for($i = 0;$i<sizeof($image_array); $i++) {
$image[$j++] = rtrim($image_array[$i]);
}
# assign a random value
$r = rand(0,$count-1);
# get the size of a random image
$size = getimagesize($image[$r]);
$width = $size[0];
$height = $size[1];
$img_src = "<img src=\"$image[$r]\" width=\"$width\" height=\"$height\" alt=\"This is a Random Image\" />";

closedir ($dir_handle);
?>
<html>

<head>
</head>

<body>

<p align="center">
<? echo '$img_src; ?>[img]file:///C:/Documents%20and%20Settings/Owner/Desktop/banner.gif[/img]</p>

</body>

</html>

But I keep getting a parse error , i dont undertand when i wrote the code and tested on my machine server it was fine

intelliot · 07-23-2004, 03:53 PM

Make sure you upload it in ASCII mode.

kaz · 07-24-2004, 10:30 AM

i did. i found the problem non the less lol <? $img src ?> i had a " before and not one ending

tjoyce · 07-25-2004, 08:42 AM

...
Glad you could get it!
I'd recommend formatting your statements so it's easier to read... see my next post.

tjoyce · 07-25-2004, 08:45 AM

Quote:

Originally Posted by kaz

I got the idea from www.cosforums when the banner changes every new page

Code:

<?
# Put the SERVER PATH to image directory.
# INCLUDE trailing slash
$dir = "/home/deathqe/public_html/forum/randphotos/";
# Put the HTML PATH to image directory.
# DO NOT include trailing slash 
$html_dir = "http://www.death-eater.net/forum/randphotos";
$dir_handle = opendir($dir);
$image_array = array();
# This opens up the image directory, grabs all files with a ".jpg" extension
# and puts them into an array. You can set whatever extension you'd like here.
# Just switch out the .jpg for .gif, etc. If you have more than one extension,
# replace this line with something like this:
# if (($file !=".") && ($file !="..") && (substr($file, -4) == ".jpg") || (substr($file, -4) == ".gif"))) {
# This will pull up all .jpg OR .gifs. If you name all the images you want to pull
# a certain way (example, image-thumb.jpg or image.thumb.jpg) you can do this:
# if (($file !=".") && ($file !="..") && (substr($file, -10) == ".thumb.jpg")) {
# basically you want to put the extension in quotes and then count how many characters
# it is and place that after $file, -
while ($file = readdir($dir_handle)) {
if (($file !=".") && ($file !="..") && (substr($file, -4) == ".jpg")) {
$file_name = "$html_dir/$file";
$image_array[$file_name] = $file_name;
}
}
# sorts the array. For some reason this won't work at all
# unless this is done. Can anyone tell me why?
sort($image_array);
$count = sizeof($image_array);
# trims all the URLs of whitespace and assigns each
# item in the array a number to identify it.
for($i = 0;$i<sizeof($image_array); $i++) {
$image[$j++] = rtrim($image_array[$i]);
}
# assign a random value
$r = rand(0,$count-1);
# get the size of a random image
$size = getimagesize($image[$r]);
$width = $size[0];
$height = $size[1];
$img_src = "<img src=\"$image[$r]\" width=\"$width\" height=\"$height\" alt=\"This is a Random Image\" />";

closedir ($dir_handle);
?>
<html>

<head>
</head>

<body>

<p align="center">
<? echo '$img_src; ?>[img]file:///C:/Documents%20and%20Settings/Owner/Desktop/banner.gif[/img]</p>

</body>

</html>

But I keep getting a parse error , i dont undertand when i wrote the code and tested on my machine server it was fine

I would do this:

Code:

<?
# Put the SERVER PATH to image directory.
# INCLUDE trailing slash
$dir = "/home/deathqe/public_html/forum/randphotos/";
# Put the HTML PATH to image directory.
# DO NOT include trailing slash 
$html_dir = "http://www.death-eater.net/forum/randphotos";
$dir_handle = opendir($dir);
$image_array = array();
# This opens up the image directory, grabs all files with a ".jpg" extension
# and puts them into an array. You can set whatever extension you'd like here.
# Just switch out the .jpg for .gif, etc. If you have more than one extension,
# replace this line with something like this:
# if (($file !=".") && ($file !="..") && (substr($file, -4) == ".jpg") || (substr($file, -4) == ".gif")))
# {
#   // This will pull up all .jpg OR .gifs. If you name all the images you want to pull
#   // a certain way (example, image-thumb.jpg or image.thumb.jpg) you can do this:
#   if (($file !=".") && ($file !="..") && (substr($file, -10) == ".thumb.jpg"))
#   {
#     // basically you want to put the extension in quotes and then count how many characters
#     // it is and place that after $file, -
while ($file = readdir($dir_handle))
{
  if (($file !=".") && ($file !="..") && (substr($file, -4) == ".jpg"))
  {
    $file_name = "$html_dir/$file";
    $image_array[$file_name] = $file_name;
  }
}

# sorts the array. For some reason this won't work at all
# unless this is done. Can anyone tell me why?

sort($image_array);
$count = sizeof($image_array);

# trims all the URLs of whitespace and assigns each
# item in the array a number to identify it.

for($i = 0;$i<sizeof($image_array); $i++)
{
  $image[$j++] = rtrim($image_array[$i]);
}

# assign a random value
$r = rand(0,$count-1);

# get the size of a random image
$size = getimagesize($image[$r]);
$width = $size[0];
$height = $size[1];
$img_src = "<img src=\"$image[$r]\" width=\"$width\" height=\"$height\" alt=\"This is a Random Image\" />";

closedir ($dir_handle);
?>
<html>

<head>
</head>

<body>

<p align="center">
<? echo '$img_src'; ?>[img]file:///C:/Documents%20and%20Settings/Owner/Desktop/banner.gif[/img]</p>

</body>

</html>

... Note the for loop and the while statement, etc.

I just think it's more organized and easier to read that way...

neno.tu · 10-11-2004, 08:32 AM

I recommed you to get a PHPEditor, that helps a lot

It is like VS.NET or FrontPage...

Try Googling for a PHPEditor, that will fix your little details when programming...

I have made several scripts that didn't work at first for the stupid errors like missing a letter or a ";" or the " in self...

Hahahah programming is so perfectly design for mistakes....

Let me know about the editor :P

See ya

jahsound · 10-13-2004, 12:42 AM

If you have a MySQL database, you can also insert your pictures (or only their names) into, and after use the rand() function to select one random image on every new page.

Code:

SELECT pic_id FROM pictures ORDER BY rand()

Thread Tools
Show Printable Version Email this Page
Display Modes
Linear Mode Switch to Hybrid Mode Switch to Threaded Mode

Similar Threads
Thread	Thread Starter	Forum	Replies	Last Post
Make a random remark!	andrew247	Games and Quizzes	285	06-07-2008 09:38 AM
/random feature request	raduweiss	Google Talk	4	12-30-2005 10:44 PM
ME!, dont u just love random?	mikeskuse999	Introduce Yourself	1	07-20-2005 08:47 AM
Random image for your gallery	puccavn	Web Design, Coding & Programming Forum	0	05-05-2005 11:44 PM
Make a random remark!	andrew247	Games and Quizzes	264	01-01-1970 10:29 PM

07-23-2004, 03:53 PM	#2 (permalink)
intelliot Google Guru Join Date: May 2004 Posts: 2,527 Thanks: 15 Thanked 49 Times in 28 Posts	Make sure you upload it in ASCII mode.

07-24-2004, 10:30 AM	#3 (permalink)
kaz Noogle Join Date: Jul 2004 Location: Manchester Posts: 2 Thanks: 0 Thanked 0 Times in 0 Posts	i did. i found the problem non the less lol <? $img src ?> i had a " before and not one ending

07-25-2004, 08:42 AM	#4 (permalink)
tjoyce Junior Googler Join Date: Jul 2004 Posts: 34 Thanks: 0 Thanked 0 Times in 0 Posts	... Glad you could get it! I'd recommend formatting your statements so it's easier to read... see my next post.

10-11-2004, 08:32 AM	#6 (permalink)
neno.tu Google Freak Join Date: Oct 2004 Location: Caracas - Venezuela Posts: 365 Thanks: 0 Thanked 0 Times in 0 Posts	I recommed you to get a PHPEditor, that helps a lot It is like VS.NET or FrontPage... Try Googling for a PHPEditor, that will fix your little details when programming... I have made several scripts that didn't work at first for the stupid errors like missing a letter or a ";" or the " in self... Hahahah programming is so perfectly design for mistakes.... Let me know about the editor :P See ya

10-13-2004, 12:42 AM	#7 (permalink)
jahsound Noogle Join Date: Oct 2004 Location: Paris Posts: 4 Thanks: 0 Thanked 0 Times in 0 Posts	If you have a MySQL database, you can also insert your pictures (or only their names) into, and after use the rand() function to select one random image on every new page. Code: SELECT pic_id FROM pictures ORDER BY rand()

GoogleCommunity Sponsor
Use coupon "forum" for 50% Off!


Sponsored Links